I found the distance between ends using distance formula i.e $6$. $\Rightarrow 4a => $ $a= 3/2$ and the focus $(2,2) $ What should I do next? How to use this information in $(x-h)^2 = -4a(y-k)^2$
2026-04-12 19:53:09.1776023589
Equation of parabola whose ends of latus rectum are $(-1,2)$ and $(5,2)$
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HINT... based on what you have done, you can deduce that the vertex has coordinates $\left(2, \frac 12\right)$.