Given point A(2,5) and point B(2,-1) find the set of points whose distance from A is double the distance from B. I attempted to solved it as follows: $$\left(x-2\right)^2+\left(y-5\right)^2=2\left(\left(x-2\right)^2+\left(y+1\right)^2\right)$$ This yields: $$\left(x-2\right)^2+\left(y+7\right)^2=72$$
However, the proposed solution is: $$\left(x-\frac{2}{3}\right)^2+\left(y+3\right)^2=\frac{112}{9}$$
I can't seem to figure out where I went wrong.