The proposition $p' \cup (p\cap q')$ is equivalent to $1.$ $p\cup q'$ $2.$ $p\to q'$ $3.$ $q\to p$ $4.$ $p\cap q'$?
The given expression can be written as $(p'\cup p)\cap (p'\cup q')=1\cap (p'\cup q')=p'\cup q'$
How to proceed further?
2026-04-11 20:12:21.1775938341
Equivalent expression of $p' \cup (p\cap q')$
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