Equivelent solutions to second order ODEs

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I have worked out the solution to an ODE using two methods, with solutions as follows: $$A e^{-5t} + B e^{3t}$$ $$\text {and}$$ $$A\begin{pmatrix} \;1 \\ {-5} \end{pmatrix} e^{-5t}+B\begin{pmatrix} 1 \\ 3 \end{pmatrix} e^{3t}$$

Does the second give more information? I am not sure how to interpret the second solution. I believe that the second solution is actually two separate solutions $y$ along each line. Is that correct? Which would also make sense given that the first equation is along the top line of the second

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Suppose the solution to an ODE (say $\ddot{x} + 2\dot{x} - 15x = 0$) is given by $$x(t) = Ae^{-5t} + Be^{3t}.$$ Notice that when you differentiate this you get $$\dot{x}(t) = -5Ae^{-5t} + 3Be^{3t}$$ which is the second row of your vector solution $$ \left(\begin{matrix}x\\ \dot{x}\end{matrix}\right) =A\left(\begin{matrix}\ 1\\ -5\end{matrix}\right)e^{-5t} +B\left(\begin{matrix}1\\ 3\end{matrix}\right)e^{3t}. $$ As for which gives more information; the information is there in both. I find the second form more convenient as it has all the things i need for phase plane analysis.