Is $G$ a graph which has an isolated vertex and its other connected component is $C_{45}$ an Eulerian graph? To be an Eulerian graph, could it happen that our graph is not connected?
2026-03-26 06:05:21.1774505121
Eulerian graph with $46$ vertices and $45$ edges
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The answer depends on exact definition of Eulerian graph. It may vary for different authors.
Euler himself didn't mention any connectivity at all, even in the theorem. In the problem with bridges connectivity could look like something natural. On the other hand isolated island would be also natural. Euler couldn't know in advance that his article would become the first article in graph theory, so he didn't care much about such details.
The definition in Graph theory with applications by Bondy and Murty doesn't mention connectivity. (In this case an extra isolated vertex is allowed.)
Another definition you can find, e. g. in Exercises in Graph Theory by Melnikov et al. It is not so popular, however sometimes occurs.
There is also a rather different point of view on what to call an Eulerian graph (or Euler graph), e. g. in Linear Graphs and Electrical Networks by Seshu and Reed.
So if you are solving a problem read the definition given in the same book or in lectures. If you create a new material I would recommend using the first definition as the most relevant.