I'm reading about this theorem.
But then I see this graph, which seems to be a counter-example,
with the Eulerian trail being $e_1e_2...e_{11}$, and the odd-degree vertices being $v_1$ and $v_3$.
Am I missing something here?
I'm reading about this theorem.
But then I see this graph, which seems to be a counter-example,
with the Eulerian trail being $e_1e_2...e_{11}$, and the odd-degree vertices being $v_1$ and $v_3$.
Am I missing something here?
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Community wiki answer so the question can be marked as answered:
As noted in a comment, "Eulerian" here means "having an Euler circuit", not "having an Euler trail". Thus your Eulerian trail does not contradict the theorem.