Evaluate: $\int_{0}^{\infty}\frac{\ln^{n}(x)\ln(1+x)}{x(1+x^2)}\mathrm dx$

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Looking for the closed form of this integral

$$\int_{0}^{\infty}\frac{\ln^{n}(x)\ln(1+x)}{x(1+x^2)}\mathrm dx=G(n)$$

$n:=1,3,5,7,...$

Wolfram can evaluate it but I can't generalise into a closed form.

Can anyone help, please.

$$\int_{0}^{\infty}\frac{\ln^{3}(x)\ln(1+x)}{x(1+x^2)}\mathrm dx=\frac{1}{256}[-24\pi^2\zeta(3)-45\zeta(5)-7\pi^4\ln(4)]$$