I used substitution $$t=x-1, x=t+1,x\rightarrow1\Rightarrow t\rightarrow 0$$
Now the expression is $$\lim_{t\to\ 0}\frac{t+1+(t+1)^2+\cdots+(t+1)^n-n}{t}$$
Can we use the sum of geometric sequence or squeeze theorem?
I used substitution $$t=x-1, x=t+1,x\rightarrow1\Rightarrow t\rightarrow 0$$
Now the expression is $$\lim_{t\to\ 0}\frac{t+1+(t+1)^2+\cdots+(t+1)^n-n}{t}$$
Can we use the sum of geometric sequence or squeeze theorem?
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Hint: the numerator can be written:
$$(x-1)+(x^2-1) +\cdots + (x^n-1)$$