Evaluate the definite integral $\int_{-9}^9 (e^x-e^{-x}) dx$

Question

Section 5.4

Can somebody please verify this for me?

Evaluate $\int_{-9}^9 (e^x-e^{-x}) dx$

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$\int_{-9}^9 (e^x-e^{-x}) dx$

$= \int_{-9}^9e^x\,dx -\int_{-9}^9e^{-x} dx$

$= (e^x|_{-9}^9-\frac{e^{-x}}{-1}|_{-9}^9)$

$= ((e^9-e^{-9})-(\frac{e^{-9}}{-1}-\frac{e^{-(-9)}}{-1}))$

$= e^9-e^{-9}-\frac{e^{-9}}{-1}+\frac{e^{-(-9)}}{-1}))$

$= e^9-e^{-9}+e^{-9}-e^{9}$

$=0$

Answer 1

An odd function integrated from $-a$ to $a$ will be $0$.