Evaluate the iterated integral:
$$\int_0^2 \int_0^1 (2x+y)^8 \,dxdy$$
I tried doing a u-sub by letting u = 2x+y but then once I got to the outer integral I got $$\int_0^2 (2+y)^9/18 - y^9/18 \, dy$$ which I don't know how to integrate. Any feedback would be appreciated! Thanks in advance.
$$\int_0^2 (2+y)^9/18 - y^9/18 \, dy =\int_0^2 (2+y)^9/18 dy -\int _0^2 y^9/18 \, dy$$
you may deal with each integral separately.