Can someone evaluate the limit $\lim_{x \to 0}\frac{\sin 3x}{x}$ without applying L'Hopital's rule to $\frac{\sin 3x}{x}$ to make it $\frac{3\cos 3x}{1}=3$?
2026-04-07 14:38:29.1775572709
Evaluate the limit without applying L'Hopital?
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