Evaluating $\int_{0}^1\int_{0}^{\sqrt{4y-y^2}}x^2dxdy$ using polar coordinates

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Evaluate $$\int_{0}^1\int_{0}^{\sqrt{4y-y^2}}x^2dxdy$$ using polar coordinates.

My try: The region is as shown below:

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As i can notice $\theta$ is going from $0$ to $\frac{\pi}{2}$. But i am confused in finding limits for $r$?