We know that for $z \in \mathbb{C}$
$$ \int_C \frac{f(z)}{z-a}\ dz = f(a) $$
where $C$ is a closed contour.
Then how can we compute
$$ \int_C \frac{z^d f(z)}{z-a} dz $$
We know that for $z \in \mathbb{C}$
$$ \int_C \frac{f(z)}{z-a}\ dz = f(a) $$
where $C$ is a closed contour.
Then how can we compute
$$ \int_C \frac{z^d f(z)}{z-a} dz $$
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Let $g(z)=z^d f(z)$. Then $$\int_C \frac{g(z)}{z-a}dz = 2\pi i \cdot g(a) = 2\pi i \cdot a^d f(a)$$
assuming that $C$ is a closed, positively oriented, rectifiable curve with winding number $n=1$, enclosing the point $z=a$, and that $f(z)$ is holomorphic on the region enclosed by $C$.