Evaluating the limit $\lim_{x\to-1}\frac{\sqrt{x}-1}{x-1}$

Question

How would you solve $\displaystyle\lim_{x\rightarrow-1}\left(\dfrac{\sqrt{x}-1}{x-1}\right)$ ?

I tried multiplying it by the conjugate. I don't know how to get rid of the square root.

Answer 1

Huge hint:

\begin{equation} (\sqrt{x}-1)(\sqrt{x}+1) = x-1 \end{equation}