Could someone give examples homomorphisms of rings f: R->S and g: S->T such that gof is a monomorphism but g is not?
I tried with the maps from Z (a->na) but can't think of a map such that the composition remains injective.
Could someone give examples homomorphisms of rings f: R->S and g: S->T such that gof is a monomorphism but g is not?
I tried with the maps from Z (a->na) but can't think of a map such that the composition remains injective.
Consider the composition of rings $\Bbb Z\to \Bbb Z[X]\to \Bbb Z$, the first morphism is the inclusion $f:\Bbb Z\to \Bbb Z[X]$, mapping $n$ into the constant polynomial $n=n\cdot X^0$, the second morphism is $g:\Bbb Z[X]\to \Bbb Z$, the evaluation in zero, $g\to g(0)$. The composition is the identity, thus a monomorphism. But $g$ is of course not injective.