If x is a random gaussian noise, how can I derive the value of $$ E[x(n-a)x(n-b)]$$ $$\text{where } x(n)=\mathcal{N}(\mu,\sigma)$$
Also what if x(n) has zero mean?
Thanks
If x is a random gaussian noise, how can I derive the value of $$ E[x(n-a)x(n-b)]$$ $$\text{where } x(n)=\mathcal{N}(\mu,\sigma)$$
Also what if x(n) has zero mean?
Thanks
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