Explicit connection between vector fields and derivations

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I'm taking course on differential geometry and I have a question that I haven't been able to find an answer to.

I understand that there are two equivalent definitions of a vector field on a smooth manifold $M$:

  1. A vector field $X: M \to TM$ is a map assigning $p\mapsto X|_p$
  2. A vector field $X: C^\infty(M) \to C^\infty(M)$ whereby $f\mapsto X(f) \in C^\infty(M)$ and $X(f)(p) = \sum_{i=1}^n x^i\frac{\partial f}{\partial x^i}(p)$

However, I don't understand how these definitions work on a more explict level for calculations. For example, take the vector field $X = x\frac{\partial}{\partial x} + xy\frac{\partial}{\partial y}$on $\mathbb{R}^2$, then for some $p = (x_0,y_0)\in \mathbb{R}^2$ is $X|_p$ just $x_0\frac{\partial}{\partial x} + x_0y_0\frac{\partial}{\partial y}$?

I understand that this question is quite elementary, but I haven't been able to find an explicit answer in any textbooks or articles.

Any help would be greatly appreciated.

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The answer to your question is YES, but you must evaluate the partial derivatives at $p$ as well. This then gives you $X(f)(p)$ when you apply it to a smooth function.