$g(t) = \sqrt{1 − 8^t}$
The domain of $g(t)$ is all the values of t for which $8^t ≤ 1$. To find the upper bound of this domain, I solve $8^t = 1$ and obtain that $t ≤ 0$? Is that correct? Thanks.
$g(t) = \sqrt{1 − 8^t}$
The domain of $g(t)$ is all the values of t for which $8^t ≤ 1$. To find the upper bound of this domain, I solve $8^t = 1$ and obtain that $t ≤ 0$? Is that correct? Thanks.
Yes, this is absolutely correct.