I have an equation such that
$$1=e^{\frac{ylog(3+x)}{3+x}}-3 -x$$
Where e is the exponential function. How do I solve for x?
According to the laws of exponents, $a^{m/n}=\sqrt[n]{a^m}$,
Applying this that would leave me with,
$$1=e^{\frac{ylog(3+x)}{3+x}} =\sqrt[3+x]{e^{ylog(3+x)}}$$
Does this mean that I can simplify the expression as follow?
$${e^{ylog(3+x)-(3+x)}}$$
I'm not sure how to take it from here, any help would be greatly appreciated. Thank you