If $X$ is an exponential random variable with mean $\frac{1}{γ}$, show that $\mathbb{E}[X^k]=\frac{k!}{γ^k},\,\, k=1,2,3,\cdots$
*Use the gamma density function
$\mathbb{E}[X^k]=∫x^{k}γe^{-γx}dx$
I cannot figure out how you incorporate the gamma density function....
Whenever you see factorials popping up mysteriously in integral evaluations, you should always think of the gamma function, and in particular that fact that for any integer $n$
$$n! = \Gamma (n+1) = \int_0^{\infty}x^{n}e^{-x} dx$$
If you make a variable transform $u = \gamma x$ you should be able to massage your integral into something that looks like this.