I have the following equation
$$v=ac\exp(-ct)$$
If I square this equation, is the following correct?
$$v^2 = a^2c^2\exp(-ct)*\exp(-ct) = a^2c^2\exp(-2ct)$$
This result is because:
$$e^{(x+y)} = e^xe^y$$
"e" and "exp" are the same thing.
I have the following equation
$$v=ac\exp(-ct)$$
If I square this equation, is the following correct?
$$v^2 = a^2c^2\exp(-ct)*\exp(-ct) = a^2c^2\exp(-2ct)$$
This result is because:
$$e^{(x+y)} = e^xe^y$$
"e" and "exp" are the same thing.
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