$2^{2^{k+1}}=({2^{2^k}})^2$
$2^{2^{k+2}} = ?$
$2^{2^{k+n}} = ?$
Just can't figure it out.
Hint. Recall that $a^{b+c}=a^b\cdot a^c$ and $a^{b\cdot c}=(a^b)^c=(a^c)^b$.
Hence we have $2^{2^{k+n}}=2^{2^{k}\cdot 2^n}$. Can you take it from here?
Copyright © 2021 JogjaFile Inc.
Hint. Recall that $a^{b+c}=a^b\cdot a^c$ and $a^{b\cdot c}=(a^b)^c=(a^c)^b$.
Hence we have $2^{2^{k+n}}=2^{2^{k}\cdot 2^n}$. Can you take it from here?