To express $F$ using only $\to$ for
$$F = \overline{A \lor B} = \overline{\overline{A} \to B}$$
but you only need to use $\to$. I do not know how to get rid of negation.
To express $F$ using only $\to$ for
$$F = \overline{A \lor B} = \overline{\overline{A} \to B}$$
but you only need to use $\to$. I do not know how to get rid of negation.
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We need something like $\bot$ (tye constant that is always false) to write:
In boolean algebra we have the constants $0$ and $1$.
We have:
Thus: