Is there a good expression for the Laplace-Beltrami on a function $u$ on a sphere or a circle of radius $R>0$ in terms of the Laplacian on ambient space?
There is a formula on Wikipedia for the unit sphere: $$\Delta_{S^{n-1}}f(x) = \Delta f(x/|x|).$$ How about sphere of radius $R$?
$\newcommand{\R}{\mathbf{R}}$To confirm jena's answer: Let $S^{n-1}$ denote the sphere $\sum_{i} x_{i}^{2} = 1$, regarded merely as a smooth manifold. For $R > 0$, let $g(R)$ denote the round metric of radius $R$ on $S^{n-1}$.
The mapping $i_{R}:\bigl(S^{n-1}, g(R)\bigr) \to \R^{n}$ defined by $i_{R}(x) = Rx$ is an isometric embedding, so the image $i_{R}(S^{n-1})$ may be identified with $S^{n-1}(R)$, the sphere of radius $R$ in $\R^{n}$.
Using the argument outlined on Wikipedia, if $f:S^{n-1}(R) \to \R$ is twice continuously-differentiable, define $\hat{f}:\R^{n}\setminus\{0\} \to \R$ by $\hat{f}(x) = f\bigl(Rx/\|x\|\bigr)$, i.e., extend $f$ to be constant along rays through the origin. The induced function $\tilde{f}:S^{n-1} \to \R$ satisfies $$ \tilde{f}(x/R) = \hat{f}(x) = f(x)\quad\text{for $x$ in $S^{n-1}(R)$.} %\tilde{f}(x/\|x\|) = \hat{f}(x) = f(Rx/\|x\|)\quad\text{for $x$ in $\R^{n}$.} $$ In other words, $f$ and $\tilde{f}$ are identical as functions on the smooth manifold $S^{n-1}$, and each is obtained by restricting $\hat{f}$ to the appropriate sphere in $\R^{n}$.
Since $g(R) = R^{2} g(1)$ and the trace of the Hessian depends inversely on the metric components, $$ \frac{1}{R^{2}}\, \Delta_{S^{n-1}(R)} f = \Delta_{S^{n-1}(1)} \tilde{f} = \Delta \hat{f} $$ by the formula for the Laplacian in spherical coordinates.