$f(x)=\frac{10x}{x^2+1}$ Find greatest value of $\delta$ accurate to three decimal places that $0<|x-1|<\delta$ guaruntee $|f(x)-5|<0.01$
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2026-03-26 01:12:39.1774487559
$f(x)=\frac{10x}{x^2+1}$ Find greatest value of $\delta$ accurate to three decimal places that $0<|x-1|<\delta$ guaruntee $|f(x)-5|<0.01$
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