Let $f\in L^p(\mathbb{R}^d)$, where $1\leq p < \infty$, and $d \in \mathbb{N}$.
Then does there exist $r>0$ and a radial function $g\in L^p(B_r)$ ($g(x)=g(|x|), x\in B_r=\{x\in \mathbb{R}^d;|x|<r \}$) such that
$|f(x)|\leq |g(x)| \ a.e. x \in B_r$?
Let $f\in L^p(\mathbb{R}^d)$, where $1\leq p < \infty$, and $d \in \mathbb{N}$.
Then does there exist $r>0$ and a radial function $g\in L^p(B_r)$ ($g(x)=g(|x|), x\in B_r=\{x\in \mathbb{R}^d;|x|<r \}$) such that
$|f(x)|\leq |g(x)| \ a.e. x \in B_r$?
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