factor $x^2+1-6x^{-2}$

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I'm trying to factor $$ x^2+1-6x^{-2} $$ I don't know how to handle the $$x^{-2}$$ while having to get $$x^2$$ this is the best i can get $$ (x+3)(x-2) $$ is there exponent property or algebra property I should look for, so that i can get the answer?

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$x^2+1-6x^{-2}=(x^4+x^2-6)/x^2=(x^2+3)(x^2-2)/x^2$