Factoring an expression

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I want to prove that $$[2b^2-c(b+c)][2c^2-b(b+c)]\leq0$$ when $$ bc\leq0$$ but i don't have any clue on how to factor that expression. I tried multiplying the terms within the paranthesis but all that i got was a mess.

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Hint:

$$2x^2-xy-y^2=2x(x-y)+y(x-y)=?$$

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i have your term factorized in the form $$-(c-b)^2 (2 b+c) (b+2 c)$$