I need to find the value of 'x' in the equation $8^x + 2^x = 130$.
As you can see, my final answer at the bottom of the pic is different from what my calculator is saying.
I feel that the step in line 3, which says, $ log (8^x) + log (2^x) = log (130) $ might have something to do with the wrong answer.
Can someone give me feedback on what I worked out?
Line 3 should have said, $\log ( 8^x + 2^x ) = \log 130$.
It will also help to assume $y = 2^x$.
Then proceed to find the value of $y$, in the equation $y^3 + y -130 = 0$.