Factoring polynomials; pre-calculus

Question

$(x-y)^{2}+2(y-x)-24$

Answer: $(x-y-6)(x-y+4)$

I couldn't find a way to get to this answer, may you give me a hint in the process. Thanks!

Answer 1

Hint: $$y-x = -(x-y)$$${}{}{}{}{}$

After which you can factor in the same way considering $x-y$

Answer 2

take $T=x-y$ so we have $T^2-2T-24$. then you can factor it as $(T-6)(T+4)$

Answer 3

Hint:  complete the square $\;(x-y)^{2}-2(x-y)\color{red}{+1-1}-24= (x-y-1)^2 - 5^2\,$.