Factor $3(2x+3)^2 + 7(2x+3) - 6$
What I did:
With the substitution $X=2x+3$: \begin{align} 3(2x+3)^2 + 7(2x+3) - 6 &= 3X^2-9X+2X-6 \\ &= 3X(X-3)+2(X-3) \\ &= (X-3)(3X+2) \\ &=((2x+3)-3)(3(2x+3)+2) \\ &=(2x+0)(6x+9+2) \\ &=(2x)(6x+11) \end{align}
2026-03-28 20:57:26.1774731446
Factoring the polynomial $3(2x+3)^2 + 7(2x+3) - 6$
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Your method is correct. You made a sign error: $$...=(X+3)(3X-2)=...$$