Factorising $x^{12} + 1$ into irreducible polynomials over $\mathbb{Q} $?

Question

I calculated that $x^{12} + 1 = (x^4 + 1)(x^8 - x^4 + 1)$

I also know that $x^4 + 1$ is irreducible using Eisenstein's Criterion with $ p=2$ and substituting $x$ with $x + 1$.

My question is, how can I prove that $x^8 - x^4 + 1$ is irreducible?

I tried using Eisenstein's Criterion again but I can't come up with the right substitution and prime.

Am I missing something?