Factorize $(5a + \frac23)^2* (2a - \frac12)^2$

Question

I found this question in my textbook - $$\left(5a + \dfrac23\right)^2\cdot \left(2a - \dfrac12\right)^2$$ I think it is already factorized but is there a way I can factorize it some more ? I tried combining both the terms but to no avail. I just don't know how to go about doing this one.

Answer 1

$$ \frac{(2+a(7-60a))^2}{36} $$

Answer 2

The only simplification I can think of here is:$$(5a + \dfrac23)^2* (2a - \dfrac12)^2=\frac{(15a+2)^2}{9}\cdot\frac{(4a-1)^2}{4}=\frac{((15a+2)(4a-1))^2}{36}$$

Answer 3

You are quite right in saying that it is factorized allready. You could clean it up a bit by getting rid of the fractions in the factors, but that's all.