Fastest Method to solve this average problem

Question

average of A and B is 71; of B and C is 76; of A and C is 79. How to find the average of A,B,C. I know the way of solving this problem using equations.But it takes time.So wanted to know if any other logic can be applied to it to solve faster.

Answer 1

What could be faster than:

$\frac{A+B+C}{3} = \frac{\frac{A+B}{2}+\frac{B+C}{2}+\frac{A+C}{2}}{3} = \frac{71+76+79}{3}$

Answer 2

Just add the averages and divide by $3$: $$\frac{A+B}2+\frac{A+C}2+\frac{B+C}2=A+B+C\;\;.$$

Answer 3

Add the three averages, you get $A+B+C$ (because first average is $\frac{A}{2}+\frac{B}{2}$, etc); then divide by $3$. So $$\frac{1}{3}(71+76+79) = \frac{226}{3}.$$

Answer 4

A trick you might use (if you're doing this in your head) is to "center" the numbers on a guess near the average, and then compute the average offset and add back the guess.

For example, for your three numbers $71, 76, 79,$ I would guess the average is around $75$. So now I take the offsets from my guess: $-4, 1,$ and $4$. Next, take the average of these 3 numbers, which is clearly $1/3$. And last, add back $75$, so the answer becomes $75 \frac{1}{3}$.