The sum of zeros is the opposite of the coefficient of X, so that... $k$ is equal to $1$. Expand $(X-r_1)(X-r_2)$ to convince yourself.
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Hint: Use Vieta's formulae.$$$$
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let $x_1,x_2$ be the roots of equation $$ax^2+bx+c=0$$ from Viete formulas $$x_1+x_2=-b/a,x_1x_2=c/a$$ in your equation $a=1,b=-3k,c=-14$ then $$x_1+x_2=-(-3k)/1=3k$$
because $3k=3$ follow that $k=1$
The sum of zeros is the opposite of the coefficient of X, so that... $k$ is equal to $1$. Expand $(X-r_1)(X-r_2)$ to convince yourself.