If this equation has a solution, then 'a' is equal to
None of these
How should I proceed in this problem?
As suggested by Daniel Fischer, $-1\le \dfrac{x^2}{3}-4x+13\le1$ gives $x\le 6$ is one of the possibilities. If we put $x=6$ in the given equation, we get $\sin \dfrac{a}{6}=1$. Thus $a={3(4n+1)\pi}$.
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As suggested by Daniel Fischer, $-1\le \dfrac{x^2}{3}-4x+13\le1$ gives $x\le 6$ is one of the possibilities. If we put $x=6$ in the given equation, we get $\sin \dfrac{a}{6}=1$. Thus $a={3(4n+1)\pi}$.