I want to find the equation for the line that is perpendicular to $L_{1}$: L1 equation
Passes through $p=(3,1,-2)$, and cuts $L_{1}$.
I've been finding the dot product between direction vector of $L_{1}$ and direction vector of the requested line:
$$d1\cdot d2 = -a+2b-3c = 0,$$ then both lines must be perpendicular, with $(-1,1,1)$ that's true but I don't know how to make that the line cuts $L_{1}$. Thak you very much.