Find initial velocity of ball??

Question

A basketball match is played on a level court.A player standing at origin throws a ball from height $2.1 m$ with velocity $V=ai+ bj+2.8k$. Another player standing at $10i +4j$ starts running with velocity $v=-3i -4j \space ms^{-1}$ towards the ball when it's thrown.He catches it $1.4 m$ above ground level. Assume acceleration is $-9.8k$

Find initial velocity and horizontal distance travelled by ball.

Answer 1

Hint:

First, find the time taken by the boy to reach $ai+bj$ from $10i+4j$ with a velocity $-3i-4j \space ms^{-1}$ using $v=\frac{s}{t}.$

Now, for the ball, you have the acceleration, displacement and time. So, use $s=ut\pm \frac{1}{2}at^2.$

Answer 2

Here is the solution. I think the solution you arrived at is wrong and the correct solution is given below Good luck