I proved that for a positive semidefinite matrix holds: $$ x^TAx =0 \Rightarrow Ax=0. $$
I wanted to come up with an counterexample for an indefinite say $2 \times 2$ matrix:
So there is a $x$, such that $$ x^TAx =0, $$ but $Ax\ne 0$.
How can I construct such a counterexample.
Let $$A=\begin{pmatrix}0&1\\1&0\end{pmatrix}$$
And let $x=(0,1)$