Let f be a continuously differentiable real-valued function on [0,1] such that $\int_{1/3}^{2/3} f(x)dx = 0$. Find the minimum value of $$I = \frac{\int_{0}^{1}f′(x)^2 dx} {(\int_{0}^{1}f(x)dx)^2}$$
2026-04-06 15:56:04.1775490964
Find minimum value of this integral expression.
61 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in CALCULUS
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