I have a very basic question but I can not wrap my head around it.
We use this formula for the equation of a straight line:
$$Ax + By = Ax_0 + By_0$$
Where $A$ and $B$ are the $x$ and $y$ coordinates of a normal vector and $x_0$ and $y_0$ are coordinates of a given point on the line.
$$\begin{array}{c} \mathbf n(A;B)\\ P(x_0;y_0)\end{array}$$
Usually we have something like:
$$2x-3y = 7$$
And we know that the coordinates of this line's normal vector are $2$ and $-3$.
But now, I have this linear equation:
$$ x-8.4 = 0$$
How do I get the coordinates of this line's normal vector as there is no $Y$ value?
What if you wrote it as $1x + 0y = 8.4$