Find number of possible values satisfying the equation: $$\cos \left(\pi\sqrt{x-4}\right)\cos \left(\pi\sqrt{x}\right)=1$$
We are required to find the number of possible solutions for $x\in\Bbb R$.
I can't understand how to approach this.
Find number of possible values satisfying the equation: $$\cos \left(\pi\sqrt{x-4}\right)\cos \left(\pi\sqrt{x}\right)=1$$
We are required to find the number of possible solutions for $x\in\Bbb R$.
I can't understand how to approach this.
Hint:
Since $\cos \theta \in [-1,1]$, and we're given the equation
$$\cos(\pi \sqrt{x - 4}) \cos(\pi \sqrt x) = 1$$
then either
$$\cos(\pi \sqrt{x - 4}) = \cos(\pi \sqrt x) = 1$$
or
$$\cos(\pi \sqrt{x - 4}) = \cos(\pi \sqrt x) = -1$$
Don't forget to invoke the periodicity of cosine as well.