Find parametric equations for the arc of a circle of radius $6$ from $P=(0,0)$ to $Q=(12,0)$

Question

My Dilemma

I'm having trouble finding out the first step to this problem.

So far all I have is:

$$ \begin{align*} x(t) &= 6\cos(t) + 6\\ y(t) &= 6\sin(t) \end{align*} $$

The Question

Find parametric equations for the arc of a circle of radius $6$ from $P=(0,0)$ to $Q=(12,0)$.

$$ \begin{align*} x(t) &= \text{___}\\ y(t) &= \text{___}\\ \text{___}\ < \ &t < \text{___} \end{align*} $$

Answer 1

You already almost completed the problem. The only other question is what values of t should we use. The starting point is given as $(12,0)$, which corresponds to $t=0$ or $t=2\pi$ in your equation. The ending point is given as $(0,0)$, which corresponds to $t=\pi$ in your equation. Thus, if we restrict ourselves to $0<t<2\pi$, the answer could either be $0<t<\pi$ or $\pi<t<2\pi$, depending on if you want the top or bottom arc of the circle.