Well the derivative of the step response would be the impulse response, from which we can obtain the system function(inverse Laplace). We can roughly approximate the function in the graph, by looking at the time constant(approx, .002) and the asymptote(.75)
$$c(t)=0.75(1- e^{-\frac{t}{0.002}})$$ and hence the derivative would be, $$h(t)=\frac{0.75}{0.002}e^{-\frac{t}{0.002}}$$ whose inverse would be $$H(s)=\frac{0.75/0.002}{s+\frac{1}{0.002}}$$
Which is the transfer function. So there's one pole at s= -500
Well the derivative of the step response would be the impulse response, from which we can obtain the system function(inverse Laplace). We can roughly approximate the function in the graph, by looking at the time constant(approx, .002) and the asymptote(.75) $$c(t)=0.75(1- e^{-\frac{t}{0.002}})$$ and hence the derivative would be, $$h(t)=\frac{0.75}{0.002}e^{-\frac{t}{0.002}}$$ whose inverse would be $$H(s)=\frac{0.75/0.002}{s+\frac{1}{0.002}}$$ Which is the transfer function. So there's one pole at s= -500