The number $X$ of calls to a mental health support line has been identified as following a Poisson distribution with a rate of $10$ per hour.
Find the probability of $3$ calls in one hour AND $6$ in the next hour, stating the assumption you are making in this calculation.
I found the $$P(3 \text{ calls})=\frac{^}{x!} e^{(−)}(e)^{(-)},$$
$P(x=3)=0.00757$. But how do I figure out the probability of $6$ calls in the next hour so I can multiply them?
I'm assuming that events occur singly, and the probability of two events occurring simultaneously is zero.