find the 10's complement of given number

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Question

Find the $10$'s complement of decimal number $00,000,000$

My Approach

$r^{'s}$ complement of $N$=$r^{n}-N$

where $n$= number of digitin $N$

Now $10^{'s}$ complement of $00,000,000$=

$10^{8}-00,000,000=100,000,000$

Everywhere answer is $00,000,000$

Am i Wrong?

Please help me out!

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On BEST ANSWER

$-0=0$ so you would like the tens complement to be $0$. If you have eight digits of $0$s you don't store the ninth digit so ignore the leading $1$.