Find the co-ordinates of the point on the curve

Question

Calculate the points on the curve $y=(1-x)^4$ at gradient = -4

I solve little bit

$\frac{dy}{dx} = 4(1-x)^{4-1}\cdot \frac{d}{dx} (1-x)\\ = 4(1-x)^3 \cdot (-1 )$

the gradient is =-4 so I put it in the equation

$-4 = -4(1-x)^3$

what i should do next

Answer 1

The parametric form of the curve is $[t,(1-t)^4]$

$$\frac{dy}{dx}_{(\text{at }x=t)}=-4(1-t)^3$$

So, we need $-4(1-t)^3=-4$

Solve for $t$

Can you take it from here?