I don't think it's a matter of simple 1 - 2t = 0, 3t = 0, because then there are two values of t.
2026-03-25 12:49:47.1774442987
Find the coordinates of the point where r(t) = (2+t)i + (1-2t)j + 3t k intersects the yz plane?
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By definition, the $yz$-plane is the set $$\{(0,y,z)\mid y,z \in \mathbb{R}\}$$ so to find the intersection, set the $x$-component to $0$, and solve for $t$.