Find the equation of an exponential function knowing that its gradient=y coordinate

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Find the equation of an exponential function knowing that its gradient=y coordinate.

$f(x)=k^x$ What values would have to take $k$?

The $y$ coordinate has to be equal to the gradient, e.g. in $y=1$, the gradient has to be $1$.

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If you are given that

$$f(x)=k^x$$

then $$f'(x)=k^x\log k=f(x)$$ is achieved when $$\log k=1.$$