Find the factorization of the polynomial as a product of irreducible

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Find the factorization of the polynomial $x^5-x^4+8x^3-8x^2+16x-16$ as a product of irreducible on rings $R[x]$ and $C[x]$

Testing with the simplest possible root in this case, $P(1)=0$

Applying the schema of Ruffini

$ \begin{array}{c|lcr} & 1 & -1 & 8 & -8 & 16 & -16 \\ 1 & & 1 & 0 & 8 & 0 & 16 \\ \hline & 1 & 0 & 8 &0 &16 & 0 \\ \end{array} $

$P(x)=(x-1).(x^4+8x^2+16)$

$P(x)=(x-1).(x^2+4)^2 \rightarrow Irreducible$ $in$ $R[x]$

So, I must to factorize this to make it irreducible in $C[x]$

Applying Bhaskara in $(x^2+4)^2$ $a=1; b=0; c=4$

$$\frac{\pm\sqrt{-4.1.4}}{2}=\frac{\pm\sqrt{-16}}{2}= R_1, R_2$$ $R_1=-2i$

$R_2=2i$

So (...)

$P(x)= (x-2i).(x+2i).(x-1) \rightarrow Irreducible $ $in $ $C[x]$

this is well done?